Bhaskara's Formula (beeCrowd- 1036) URI 1036 Solution C, Python

Bhaskara's Formula beeCrowd 1036 URI 1036 Solution C Python problem solve solution solved coding Impossivel calcular discriminant sqrt r1 r2 x1 x2 1 2

Bhaskara's Formula

Read 3 floating-point numbers (double). Print the result with 5 digits after the decimal point. if it is impossible to calculate print the message "Impossivel calcular"

The formula is:

1. Take input. 
2. Calculate the value of discriminant(d) with the formula: b²-4ac.
3. Next, if the value of discriminant(d) is less than or if the value of a is zero then print "Impossivel calcular".
4. Else calculate the value of x1(R1) and x2(R2) with this formula: (-b±Öd)/2a. note that you need to calculate 2 values. One for plus and one for minus. And then print both values as said on that site.

The solution in C:

#include <stdio.h>

int main() {
    double a,b,c,R1,R2;
    scanf("%lf %lf %lf",&a,&b,&c);
    double D = (b*b)-(4*a*c);
    if(D<0){
        printf("Impossivel calcular\n");
    }
    else if(a==0){
        printf("Impossivel calcular\n");
    }
    else{
        R1 = (-b+sqrt(D))/(a+a);
        R2 = (-b-sqrt(D))/(a+a);
        printf("R1 = %0.5f\n",R1);
        printf("R2 = %0.5f\n",R2);
    }
    return 0;
}

The solution in Python:

import math;

a,b,c=map(float, input().split(" "))
d = ((b*b)-(4*a*c));
if d>=0:
    print("Impossivel calcular")
elif a==0:
    print("Impossivel calcular")
elif d>0:
    x1 = ((-b+math.sqrt(d))/(2*a))
    x2 = ((-b-math.sqrt(d))/(2*a))
    print(f"R1 = %0.5f\nR2 = %0.5f" % (x1,x2))