Interval (beeCrowd- 1037) URI 1037 Solution C, Python

Interval beeCrowd 1037 URI Solution C Python programming coding solution solved explained formula loop easy what judge auto test bee Neilor Tonin braz

Interval

The formula is:

1. Take input. 
2. Create a list of numbers that are given as intervals. The list will have one number once.
3. Loop through the list.
4. If the index is at 100 then it means it is out of range. Print "Fora de intervalo"
5. If your input is zero or greater than your current index(loop value ex: i)," and it is less than the next index(ex:i+1). Print "Intervalo -->([<--i,i+1]" note that if the number is at the first interval you will have to print "(". For other intervals you will have to print "[".

N.B: "[" means include the first number. Whereas "(" means do not include the first number.

The solution in C:

#include <stdio.h>

int main() {
 
    double x;
    scanf("%lf",&x);
    int listed[6] = {0,25,50,75,100,10000};
    int i=0;
    while(i<=4){
        if(i==4){
            printf("Fora de intervalo\n");
            break;
        }
        if((x==0 || listed[i]<x) && x<=listed[i+1]){
            if(i==0){
                printf("Intervalo [%d,%d]\n",listed[i],listed[i+1]);
                break;
            } else{
                printf("Intervalo (%d,%d]\n",listed[i],listed[i+1]);
                break;
            }
        }
        i++;
    }
 
    return 0;
}

The solution in Python:

x = float(input())
listed = [0,25,50,75,100,10000]
i=0;

while i<=4:
    if i==4:
        print("Fora de intervalo")
        break
    if (x==0 or listed[i]<x) and x<=listed[i+1]:
        if i==0:
            print("Intervalo [%d,%d]" % (listed[i],listed[i+1]))
            break
        else:
            print("Intervalo (%d,%d]" % (listed[i],listed[i+1]))
            break
    i+=1